A) zero
B) F
C) \[F(L-X)L\]
D) \[F(L-X)/M\]
Correct Answer: C
Solution :
As, acceleration \[a=\frac{f}{m}\] From FED we get \[F-T=\frac{M}{L}\,(x)\,a\] \[\Rightarrow \] \[T=F\left( 1-\frac{X}{L} \right)\] \[\Rightarrow \] \[T=\frac{F(L-X)}{L}\]You need to login to perform this action.
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