A) \[55\,g\]
B) \[11\,g\]
C) \[22\,g\]
D) \[44\,g\]
Correct Answer: A
Solution :
\[\underset{(20+12+48=80)}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{{}}\underset{(12+32=44)}{\mathop{C{{O}_{2}}}}\,\] \[\because \] \[80\,g\] \[CaC{{O}_{3}}\] produces \[=44\,C{{O}_{2}}\] \[\therefore \] \[100\text{ }g\] \[CaC{{O}_{3}}\] produces \[=\frac{44}{80}\times 100=55g\]You need to login to perform this action.
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