A) \[28.5\text{ }KJ\]
B) \[17.1KJ\]
C) \[45.7\text{ }KJ\]
D) \[1.7\,KJ\]
Correct Answer: C
Solution :
\[0.5\,mol\,HN{{O}_{3}}\equiv 0.5mol\,\,{{H}^{+}}\] and \[0.3\,mol\,O{{H}^{-}}\] \[0.5{{H}^{+}}_{(aq)}+0.3OH_{(aq)}^{-}\xrightarrow{{}}0.5{{H}_{2}}{{O}_{(l)}}\] \[\Delta H=0.8\times 57.1\] \[=45.68\,KJ=45.7\,KJ\]You need to login to perform this action.
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