A) density
B) pressure
C) KE per mol
D) \[{{V}_{rms}}\]
Correct Answer: D
Solution :
(i) Density of a gas \[\left( \rho \right) = \frac{PM}{RT}\] Since \[\frac{{{M}_{B}}}{{{T}_{B}}}=\frac{{{M}_{A}}}{{{T}_{A}}}\], \[\therefore \] at the same pressure \[={{\rho }_{A}}={{\rho }_{B}}.\] But if pressure is different, then \[{{\rho }_{A}}\ne {{\rho }_{B}}.\] (ii) Pressure of the gases would be equal if their densities are equal otherwise not. (iii) \[\operatorname{KE}\,\,per\,\,mol\,\,=\,\,\frac{3}{2}RT\] \[\therefore \] It will be different for the two gases. (iv) \[{{V}_{rms}}=\sqrt{\frac{3RT}{M}},\] since \[\frac{{{T}_{A}}}{{{M}_{A}}}=\frac{{{T}_{B}}}{{{M}_{B}}}\]; \[{{V}_{rms}}\] of \[A={{V}_{rms}}\,\,of\,\,B\]You need to login to perform this action.
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