A) \[30.7 J{{K}^{-1}} mol{{e}^{\,-1}}\]
B) \[60.3 J{{K}^{-1}} mol{{e}^{\,-1}}\]
C) \[90.8 J{{K}^{-1}} mol{{e}^{\,-1}}\]
D) \[108.9 J{{K}^{-1}} mol{{e}^{\,-1}}\]
Correct Answer: D
Solution :
\[\Delta {{H}_{vap}}=2.257\,\,KJ/g=(2.257\times 18)\,\,kJ\,mol{{e}^{-1}}\] \[=\,\,\,40.626\] \[\Delta {{S}_{vap}}=\frac{40.626}{373}=0.1089\,\,kJ\,\,{{K}^{-\,1}}\,mol{{e}^{-\,1}}\]You need to login to perform this action.
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