A) \[N{{N}_{3}}\]
B) THF
C) DIGLYME
D) All of these
Correct Answer: D
Solution :
all three have lone pairs of electrons to form a co-ordinate bond with electron deficient boron atom in \[B{{H}_{3}}\]. Due to which \[B{{H}_{3}}\] keeps in monomeric form.You need to login to perform this action.
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