A) \[BC{{l}_{3}}>BB{{r}_{3}}>B{{F}_{3}}>B{{l}_{3}}\]
B) \[B{{F}_{3}}<BB{{r}_{3}}<BC{{l}_{3}}<B{{l}_{3}}\]
C) \[B{{F}_{3}}<BC{{l}_{3}}<BB{{r}_{3}}<B{{l}_{3}}\]
D) \[B{{F}_{3}}>BC{{l}_{3}}>BB{{r}_{3}}>B{{l}_{3}}\]
Correct Answer: C
Solution :
This cannot be explained on the basis of electronegativity of substituent attached actually. This can be explained on the basis of \[{{p}_{\pi }}-{{p}_{\pi }}\] back bonding, greater the \[{{p}_{\pi }}-{{p}_{\pi }}\] back bonding lower is its lew is acidic strength \[\to \] Back bonding tendency decreases \[\to \] Lewis acidity increases.You need to login to perform this action.
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