NEET Sample Paper NEET Sample Test Paper-76

  • question_answer
                                                                  If angle between two vectors X and Y is \[120{}^\circ \], then its resultant Z will be

    A)  \[\left| Z \right|=\left| X\,-Y \right|\]                   

    B)  \[\left| Z \right|<\left| X\,-Y \right|\]

    C)  \[\left| Z \right|>\left| X\,\,-\,\,Y \right|\]             

    D)  \[\left| Z \right|=\left| X+Y \right|\]  

    Correct Answer: B

    Solution :

    If \[\left| Z \right|\] is resultant between X and Y, then \[\left| Z \right| = \sqrt{{{X}^{2}}+{{Y}^{2}}+ 2XYcos 120{}^\circ }\] \[=\,\,\,\sqrt{{{X}^{2}}+{{Y}^{2}}-XY}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ as\,\,cos\,\,120{}^\circ \,\,=\,\,\frac{-1}{2} \right]\] Similarly, \[\left| \operatorname{X} - Y \right| \,=\,\,\sqrt{{{X}^{2}}+{{Y}^{2}}-2XY\,\,cos\,\,120{}^\circ }\] \[=\,\,\,\,\sqrt{{{X}^{2}}+{{Y}^{2}}+XY}\]\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\left| X\,\,-\,\,Y \right|>\,\,\left| Z \right|\]


You need to login to perform this action.
You will be redirected in 3 sec spinner