A) \[\frac{A}{4}\]
B) \[\frac{A}{2}\]
C) \[\frac{3A}{4}\]
D) None of these
Correct Answer: B
Solution :
According to question, \[\operatorname{Potential} energy = \frac{1}{4} \left( total energy \right)\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}=\frac{1}{4}\left( \frac{1}{2}m{{\omega }^{2}}{{A}^{2}} \right)\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y=\frac{A}{2}\]
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