A) M
B) \[\frac{M}{2}\]
C) 2 M
D) 4 M
Correct Answer: C
Solution :
Since, \[h=\frac{2T\,\cos \,\,\theta }{r\rho h}\,\,i.e.,\,\,h\propto \frac{1}{r}\] As, r changes to 2 r then h will become\[\frac{h}{2}\]. \[\operatorname{Mass} of water in tube = volume \times density\] \[=\,\,\,\,\,\,\pi {{(2r)}^{2}}\frac{h}{2}\rho \] \[=\,\,\,\,2\left( \pi {{r}^{2}}h\rho \right) =2\,M\]You need to login to perform this action.
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