A) tetrahedral
B) square planar
C) sea-saw
D) trigonal monopyramidal
Correct Answer: A
Solution :
Structure of \[{{\left[ Ni{{(CN)}_{4}} \right]}^{2\,-}}\] Oxidation state of Ni in \[\left[ Ni {{\left( CN \right)}_{4}} \right]\] is + 2 Electronic configuration of \[N{{i}^{2+}}\,\,=\,\,\left[ Ar \right]3{{d}^{8}}\,4{{s}^{0}} 4{{p}^{0}}\,in {{\left[ Ni {{\left( CN \right)}_{4}} \right]}^{2}}^{-}\] \[Structure = square planar\]You need to login to perform this action.
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