A) \[2.92\,\,\times \,\,1{{0}^{15}}m/s\]
B) \[3.65 \times 1{{0}^{14}}\,m/s\]
C) \[3.65 \times 1{{0}^{16}} m/s\]
D) \[3.45 \times 1{{0}^{15}} m/s\]
Correct Answer: A
Solution :
\[\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\]where, \[{{\operatorname{n}}_{1}} = lower energy level\] \[{{\operatorname{n}}_{2}}=higher energy level.\] \[\frac{1}{\lambda }=109700\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{3}^{2}}} \right]\] \[\frac{c}{\lambda }=109700\times 3.0\times {{10}^{10}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{9} \right]\] \[=\,\,\,2.92\times 1{{0}^{15}}\,m/s\]You need to login to perform this action.
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