A) \[{{({{C}_{2}}{{H}_{5}})}_{2}}CHCl\]
B) \[{{(C{{H}_{3}})}_{3}}CCl\]
C) \[{{(C{{H}_{3}})}_{2}}CHCl\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: D
Solution :
Nucleophilic substitution bimolecular \[\left( {{S}_{N}}^{2} \right)\] prefers less sterically hindered site to attack. Lesser the steric windrance better the \[{{S}_{N}}^{2}\] reaction. So ease the reaction is \[{{1}^{o}}>{{2}^{o}}>{{3}^{o}}.\] \[{{S}_{N}}^{2}\]involves inversion of configuration stereo-chemically.
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