A) 8.1, 0.67
B) 8.1, 1.2
C) 6.4, 1.2
D) 6.4, 0.67
Correct Answer: C
Solution :
[c] \[\frac{1}{\lambda }=R\left( \frac{1}{{{n}_{1}}^{2}}-\frac{1}{{{n}_{2}}^{2}} \right)\] where R = Rydberg constant \[\frac{1}{{{\lambda }_{32}}}=\left( \frac{1}{4}-\frac{1}{9} \right)=\frac{5}{36}\] \[\Rightarrow \] \[{{\lambda }_{32}}=\frac{36}{5}\] Similarly solving for \[{{\lambda }_{31}}and\,{{\lambda }_{21}}\] \[{{\lambda }_{31}}=\frac{9}{8}\]and\[{{\lambda }_{21}}=\frac{4}{3}\] \[\therefore \] \[\frac{{{\lambda }_{32}}}{{{\lambda }_{31}}}=6.4\] and \[\frac{{{\lambda }_{21}}}{{{\lambda }_{31}}}\simeq 1.2\]You need to login to perform this action.
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