A) 16 : 1
B) 1 : 16
C) 1 : 4
D) 4 : 1
Correct Answer: A
Solution :
[a] Current flowing through the conductor, \[I=ne{{v}_{d}}A\]. Hence \[\frac{4}{1}=\frac{ne{{v}_{d1}}\pi {{(1)}^{2}}}{ne{{v}_{d2}}\pi {{(2)}^{2}}}\] or \[\frac{{{v}_{d1}}}{{{v}_{d2}}}=\frac{4\times 4}{1}=\frac{16}{1}.\]You need to login to perform this action.
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