Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds? |
1. \[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\] |
2. \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\] |
3. \[C{{H}_{3}}-C{{H}_{2}}C\equiv CH\] |
4. \[C{{H}_{3}}-CH=C{{H}_{2}}.\] |
A) Bromine in carbon tetrachloride
B) Bromine in acetic acid
C) Alk\[KMn{{O}_{4}}\]
D) Ammonical silver nitrate.
Correct Answer: D
Solution :
[d] \[B{{r}_{2}}\]in\[CC{{l}_{4}}\][a],\[B{{r}_{2}}\]in \[C{{H}_{3}}COOH\][b]and alk. \[KMn{{O}_{4}}\][c] will react with all unsaturatec compounds, i.e., 1, 3 and 4 while ammonical \[AgN{{O}_{3}}\][d] reacts only with terminal alkynes. i.e., 3 and hence compund 3 can be distinguished from 1, 2 and 4 by ammonical \[AgN{{O}_{3}}\][d].You need to login to perform this action.
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