A) 4.67
B) 28
C) 14
D) 2.33
Correct Answer: A
Solution :
[a] \[{{N}_{2}}=3{{H}_{2}}=6H\] \[\therefore \] \[1H=\frac{{{N}_{2}}}{6}\] Thus, equivalent weight of \[{{N}_{2}}\] \[=\frac{\text{molar}\,\,\text{mass}}{6}=\frac{28}{6}=4.67\]You need to login to perform this action.
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