A) 4 N
B) 8 N
C) 12 N
D) zero
Correct Answer: A
Solution :
[a] At \[t=2\,\sec ,\] \[F=2\times 2=4\,\,N,\] where as \[{{f}_{\max }}={{\mu }_{N}}=8N.\] As the applied force is less than the limiting force of friction, the frictional force will be equal to applied force i.e. \[F=2\times 2=4\,N\]You need to login to perform this action.
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