A) \[-\frac{Q}{4}\left( 1+2\sqrt{2} \right)\]
B) \[\frac{Q}{4}\left( 1+2\sqrt{2} \right)\]
C) \[-\frac{Q}{2}\left( 1+2\sqrt{2} \right)\]
D) \[\frac{Q}{2}\left( 1+2\sqrt{2} \right)\]
Correct Answer: B
Solution :
[b] For the system to be in equilibrium, net force on each of the charges must be zero. Net for on any of - Q to be zero, we have \[\sqrt{2}k\frac{{{Q}^{2}}}{{{Q}^{2}}}+k\frac{{{Q}^{2}}}{2{{a}^{2}}}-\frac{kQq}{{{a}^{2}}/2}=0\] \[\therefore \] \[q=\frac{Q}{4}(1+2\sqrt{2})\]You need to login to perform this action.
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