A) momentum \[=\frac{mvM}{M+m}\]
B) kinetic energy \[=\frac{m\,{{V}^{2}}}{2}\]
C) momentum \[=\frac{m\,V(M+m)}{M}\]
D) kinetic energy \[=\frac{{{m}^{2}}\,\,{{v}^{2}}}{2(M+m)}\]
Correct Answer: D
Solution :
[d] If V is velocity of combination (bag + bullet), then from principle of conservation of linear momentum \[(m+M)V=m\,v\,\,or\,\,V=\frac{mv}{(m+M)}\] \[K.E=\frac{1}{2}(m+M){{V}^{2}}=\frac{{{m}^{2}}\,{{v}^{2}}}{2(m+M)}\]You need to login to perform this action.
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