A) 410
B) 25
C) 1850
D) 925
Correct Answer: D
Solution :
[d] Using equipartition of energy, we have \[\frac{6}{2}KT=mCT\] \[C=\frac{3\times 1.38\times {{10}^{-23}}\times 6.02\times {{10}^{23}}}{27\times {{10}^{-3}}}\] \[\therefore \] \[C=925\,\,J/kgK\]You need to login to perform this action.
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