A) 1
B) 6
C) 4
D) 2
Correct Answer: C
Solution :
[c] Given: Percentage of the iron = 0.334%; Molecular weight of the haemoglobin = 67200 and atomic weight of the iron = 56. We know that the number of iron atoms \[\text{=}\frac{\text{Molecular}\,\,\text{w}\text{.t}\,\,\text{of}\,\,\text{haemoglobin }\!\!\times\!\!\text{ }\!\!%\!\!\text{ }\,\,\text{of}\,\,\text{iron}}{\text{100 }\!\!\times\!\!\text{ Atomic}\,\,\text{weight}\,\,\text{of}\,\,\text{iron}}\] \[=\frac{67200\times 0.334}{100\times 56}=4\]You need to login to perform this action.
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