A) \[P{{b}^{2+}}\]
B) \[C{{u}^{2+}}\]
C) \[C{{o}^{2+}}\]
D)
Correct Answer: C
Solution :
[c] \[C{{o}^{2+}}\] ion is precipitated by \[{{H}_{2}}S\] in presence of \[N{{H}_{4}}OH\] which is a group reagent of group IV in cationic analysis.You need to login to perform this action.
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