A) velocity of the particle at B is V
B) velocity of the particle at B is V \[\cos \theta \]
C) velocity of the particle at B is \[V\tan \theta \]
D) the time of flight from A to B is \[\frac{V}{g\sin \theta }\]
Correct Answer: D
Solution :
As, \[\upsilon =u+at\] Considering the motion along the line AC \[0=\upsilon -g\,\sin \theta \,t\] \[t=\frac{\upsilon }{g\sin \theta }\] Now consider the motion along the line C. \[v'=0+g\cos \theta =\frac{V}{g\sin \theta }=\upsilon \cot \theta \]You need to login to perform this action.
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