A) \[15%\]
B) 50%
C) \[100%\]
D) 125%
Correct Answer: D
Solution :
Kinetic energy \[\varepsilon =\frac{1}{2}m{{\upsilon }^{2}}\] \[\frac{\Delta \varepsilon }{\varepsilon }\times 100=\frac{V{{'}^{2}}-{{V}^{2}}}{{{V}^{2}}}\times 100\] \[=[{{(1.5)}^{2}}-1]\times 100\] \[\frac{\Delta E}{E}\times 100=125%\]You need to login to perform this action.
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