The remainder when \[{{17}^{200}}\] is divided by 18, is |
A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
We know that, \[({{x}^{m}}-{{a}^{m}})\] is divisible by \[(x+a)\] for even value of m. |
\[\therefore \] \[({{17}^{200}}-{{1}^{200}})\] is divisible by \[(17+1)\] |
\[({{17}^{200}}-1)\] is divisible by 18. |
When \[{{17}^{200}}\] is divisible by 18, then the remainder is 1. |
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