A) \[65{}^\circ \]
B) \[55{}^\circ \]
C) \[35{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: B
Solution :
Let \[\angle CDB=x{}^\circ \] Then, CD=CB \[\Rightarrow \]\[\angle CBD=\angle CDB=x{}^\circ \] \[\angle BCD=\angle BAD=70{}^\circ \] (opp. angles of a rhombus) \[\therefore \] \[x+x+70=180{}^\circ \] (sum of the angles a triangle is 18°) \[\Rightarrow \] \[2x=110{}^\circ \] \[\Rightarrow \] \[x=55\] \[\therefore \]\[\angle CDB=55{}^\circ \]You need to login to perform this action.
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