A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: C
Solution :
Given expression \[=\frac{1}{(1+{{\tan }^{2}}\theta )}+\frac{1}{{{(1+{{\cot }^{2}}\theta )}^{2}}}\] \[\frac{1}{{{\sec }^{2}}\theta }+\frac{1}{\cos e{{c}^{2}}\theta }=({{\cos }^{2}}\theta +{{\sin }^{2}}\theta )=1\]You need to login to perform this action.
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