A) 1860
B) 1890
C) 1845
D) 1677
Correct Answer: C
Solution :
\[A+B+C+D=42\times 4\] \[(x)+(x+2)+(x+4)+(x+6)=42\times 4\] \[4x+12=168\Rightarrow 4x=156\Rightarrow x=39\] \[B\times D=41\times 45=\mathbf{1845}\]You need to login to perform this action.
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