A) 0
B) \[1\]
C) \[-1\]
D) \[-2\]
Correct Answer: A
Solution :
\[\frac{x}{y}+\frac{y}{x}=-2\,\,\Rightarrow \,\,\,{{x}^{2}}+{{y}^{2}}=-2xy\] \[{{(x+y)}^{2}}=0\Rightarrow x+y=0\] Now, \[{{x}^{3}}+{{y}^{3}}+3xy\,(x+y)={{(x+y)}^{3}}=\mathbf{0}\]You need to login to perform this action.
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