A) 15.75
B) 16.00
C) 16.25
D) 16.75
Correct Answer: B
Solution :
\[4{{x}^{2}}+4xy+{{y}^{2}}={{(2x+y)}^{2}}\] \[=(2\times 1.75+0.5)\] \[={{(3.5+0.5)}^{2}}={{4}^{2}}=16\]You need to login to perform this action.
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