A) 6
B) \[-\,6\]
C) 10
D) \[-\,10\]
Correct Answer: D
Solution :
One root of the equation \[2{{x}^{2}}-x+k=0\,\,is-2.\] \[\therefore \] \[2{{(-2)}^{2}}-(-2)+k=0\] \[\Rightarrow \] \[8+2+k=0\] \[\Rightarrow \]\[k=-10\]You need to login to perform this action.
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