A) \[\mu >\tan \left( \frac{\pi }{4}-\frac{\theta }{2} \right)\]
B) \[\mu <\tan \left( \frac{\pi }{4}-\frac{\theta }{2} \right)\]
C) \[\mu <\tan \theta \]
D) \[\mu >\tan \frac{\pi }{4}\]
Correct Answer: B
Solution :
\[{{F}_{1}}=w\sin \theta +\mu w\cos \theta \] |
\[{{F}_{2}}=w\] |
As, \[{{F}_{1}}<{{F}_{2}}\] |
\[\therefore \,\,\mu <\tan \left( \frac{\pi }{4}=\frac{\theta }{2} \right)\] |
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