| A block is given velocity 10 m/s along the fixed inclined as shown in figure from the bottom of the inclined plane. Find the total distance travelled along the inclined plane, if the coefficient of friction is equal to 0.5: |
 |
A) 5m
B) 10m
C) \[\frac{25}{3}m\]
D) \[\frac{50}{3}m\]
Correct Answer: B
Solution :
| distance travelled along inclined plane till it stops |
| \[s=\frac{{{\left( 10 \right)}^{2}}}{2\left( g\sin 37{}^\circ +\mu \cos 37{}^\circ \right)}=5\,m\] |
| But friction force is not sufficient to stop there, so it will come back to the bottom of the inclined plane. |
| Total distance travelled \[\lambda \] |
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