JEE Main & Advanced Physics NLM, Friction, Circular Motion Sample Paper Topic Test - Friction

  • question_answer
    If dimensions of velocity is \[b{{c}^{-1}},\] acceleration \[b{{c}^{-2}}\] and length \[ab,\] the dimensions of coefficient of friction are

    A) \[{{a}^{0}}{{b}^{0}}{{c}^{0}}\]                

    B) \[{{a}^{-1}}{{b}^{0}}{{c}^{0}}\]

    C) \[{{a}^{1}}{{b}^{0}}{{c}^{0}}\]                

    D) \[{{a}^{-1}}{{b}^{-1}}{{c}^{0}}\]

    Correct Answer: B

    Solution :

    Here, we look for an equation involving velocity v, acceleration g and length r and coefficient of friction \[{{\mu }_{s}}\]. We arrive at
    \[{{\mu }_{s}}=\tan \theta =\frac{{{v}^{2}}}{rg}=\frac{{{b}^{2}}{{c}^{-2}}}{b{{c}^{-2}}ab}={{a}^{-1}}{{b}^{0}}{{c}^{0}}\]

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