A) \[\frac{\upsilon (6n-9)}{2n}\]
B) \[\frac{2\upsilon (6n-9)}{n}\]
C) \[\frac{2\upsilon (2n+1)}{n}\]
D) \[\frac{2\upsilon (n-1)}{n}\]
Correct Answer: A
Solution :
| [a] \[\upsilon =an\therefore a=\frac{\upsilon }{n}\] |
| Desired displacement, |
| \[S={{S}_{n}}-{{S}_{n}}-3\] |
| \[=\frac{1}{2}a{{n}^{2}}-\frac{1}{2}a{{(n-3)}^{2}}\] |
| \[=\frac{-9}{2}a+3an\] |
| \[=\frac{\upsilon }{n}\left( 3n-\frac{9}{2} \right)\] |
| \[=\frac{\upsilon }{2n}\left( 6n-9 \right)\] |
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