A) 14 m
B) 28 m
C) 22 m
D) 20 m
Correct Answer: A
Solution :
[a] Relative velocity of one with respect to the other is 28 m/s. \[{{x}_{1}}=\frac{2g}{K}\] Time taken to overtake \[=\frac{6+8}{28}s=\frac{1}{2}s\] In this time of (1/2)s the distance travelled by the two buses is 8 m and 6 m respectively Hence, Minimum road length required for overtaking is as shown in figureYou need to login to perform this action.
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