A) 2.50
B) 1.8
C) 1.2
D) 1.3
Correct Answer: B
Solution :
| [b] \[\Delta {{T}_{f}}=i{{K}_{f}}m\] |
| \[m=\frac{100g/kg\,{{H}_{2}}O}{74.55\,g/mol\,(1.34\,m)}=1.8\]\[i=\frac{\Delta {{T}_{f}}}{{{K}_{f}}m}=\frac{{{4.5}^{o}}C}{({{1.86}^{o}}C/m)\,(1.34\,m)}=1.8\] |
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