Formation of a solution from two components can be considered as |
(i) Pure solvent \[\to \] separated solvent molecules, \[\Delta {{H}_{1}}\] |
(ii) Pure solute \[\to \] separated solute molecules, \[\Delta {{H}_{2}}\] |
(iii) Separated solvent & solute molecules \[\to \] Solution, \[\Delta {{H}_{3}}\] solution so formed will be ideal if |
A) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{3}}-\Delta {{H}_{1}}-\Delta {{H}_{2}}\]
B) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}\]
C) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}-\Delta {{H}_{3}}\]
D) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}-\Delta {{H}_{2}}-\Delta {{H}_{3}}\]
Correct Answer: B
Solution :
[b] For an ideal solution, \[\Delta {{H}_{mixing}}=0\] |
\[\Delta H=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}\] |
(According to Hess's law) |
i.e., for ideal solutions there is no change in magnitude of the attractive forces in the two components present. |
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