A) \[{{(3x-1)}^{2}}+{{(3y)}^{2}}={{a}^{2}}-{{b}^{2}}\]
B) \[{{(3x-1)}^{2}}+{{(3y)}^{2}}={{a}^{2}}+{{b}^{2}}\]
C) \[{{(3x+1)}^{2}}+{{(3y)}^{2}}={{a}^{2}}+{{b}^{2}}\]
D) \[{{(3x+1)}^{2}}+{{(3y)}^{2}}={{a}^{2}}-{{b}^{2}}\]
Correct Answer: B
Solution :
Coordinates of the vertices of a triangle are and (1, 0). So, centroid is ?. (i) and ... (ii) On squaring and adding Eqs. (i) and (ii), we getYou need to login to perform this action.
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