A) \[p=q\]
B) \[p=-q\]
C) \[pq=1\]
D) \[pq=-1\]
Correct Answer: D
Solution :
The given equation is . On comparing with , we get Equation of the bisector of angles \[\Rightarrow \,\,\,\,\,\,\,\,\,{{x}^{2}}-{{y}^{2}}=-\frac{2\,xy}{p}\] \[\Rightarrow \] \[{{x}^{2}}+\frac{2\,xy}{p}-{{y}^{2}}=0\] ... (i) But given equation of the bisector of angles is ... (ii) On comparing Eqs. (i) and (ii), we getYou need to login to perform this action.
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