JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer In Cannizzaro reaction given below \[2Ph\text{ }CHO\xrightarrow[{}]{:\overset{\text{O-}}{\mathop{OH}}\,}Ph\text{ }C{{H}_{2}}OH+pHC\overset{\bullet \,\bullet }{\mathop{O_{2}^{\text{O-}}}}\,\] The slowest step is:     AIEEE  Solved  Paper-2009

    A) the attack of: \[O{{H}^{}}\]at the carboxyl group

    B) the transfer of hydride to the carbonyl group

    C) the abstraction of proton from the carboxylic group

    D) the deprotonation of\[pH\text{ }C{{H}_{2}}OH\]

    Correct Answer: B

    Solution :

    Proton transfer is rate determining step

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