A) \[{{I}_{1}}={{I}_{2}}=\frac{B/v}{6R},I=\frac{B/v}{3R}\]
B) \[{{I}_{1}}=-{{I}_{2}}=\frac{B/v}{R},I=\frac{2B/v}{R}\]
C) \[{{I}_{1}}={{I}_{2}}=\frac{B/v}{3R},I=\frac{2B/v}{3R}\]
D) \[{{I}_{1}}={{I}_{2}}=I=\frac{B/v}{R}\]
Correct Answer: C
Solution :
\[I=\frac{2BVl}{3R}\] \[{{I}_{1}}={{I}_{2}}=\frac{BVl}{3R}\]You need to login to perform this action.
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