A) 6.25 N
B) 4.0 N
C) 12.5 N
D) 0.5 N
Correct Answer: A
Solution :
Putting\[\omega =\frac{2\pi }{.04},k=\frac{2\pi }{0.5}\] in equation \[T=\mu {{v}^{2}}=\mu {{\left( \frac{\omega }{k} \right)}^{2}}\] \[=6.25\text{ }N\]You need to login to perform this action.
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