A) azobenzene
B) azoxybenzene
C) nitrobenzene
D) aniline
Correct Answer: D
Solution :
Reduction of nitrobenzene with \[Zn/HCl\] or\[Fe/HCl\] or \[Sn/HCl\] (Reducing agents) produce aniline. \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}\xrightarrow[6[H]]{Sn/HCl}{{C}_{6}}{{H}_{5}}N{{H}_{2}}+2{{H}_{2}}O\]You need to login to perform this action.
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