A) 11N
B) 22 N
C) 33 N
D) 44 N
Correct Answer: C
Solution :
70% by weight means 70 of orthophosphoric acid is present in 100 g acid \[N=\frac{w}{Eq.wt.}\times \frac{1000}{{{V}_{(cc)}}}\] \[w=70g\] \[Eq.wt.=\frac{mol.\,mass}{no.\,of\,replaceable\,H-atoms}=\frac{98}{3}\] \[V=\frac{mass}{density}=\frac{100}{1.54}\] \[N=\frac{70\times 3\times 1000\times 1.54}{98\times 100}=33N\]You need to login to perform this action.
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