A) infinity
B) 200\[V=2-\left( \frac{2}{3.9+0.1} \right)\times 0.1\]
C) 2000 \[V=1.95V\]
D) 1000\[{{m}_{1}}{{u}_{1}}={{m}_{2}}{{v}_{2}}\]
Correct Answer: C
Solution :
Key Idea: Black fringe means destructive interference. For destructive interference, we have \[=\frac{(2n+1)\lambda }{2}\] where \[E=\sigma {{T}^{4}}\] is refractive index, \[\sigma \] is wavelength and is thickness. \[\sigma \] \[\frac{E}{E}=-\frac{2Q}{Q}\] For minima, we have \[\Rightarrow \] \[E=-\frac{E}{2}\] \[3.9\Omega \] \[\therefore \]You need to login to perform this action.
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