A) 33.7°
B) 43.7°
C) 23.7°
D) 53.7°
Correct Answer: A
Solution :
From Brewsters law the relation between polarizing angle \[V=E-ir\] and refractive index n is \[i=\frac{E}{R+r}\] Given, n = 1.5 \[\therefore \] \[V=E-\left( \frac{E}{R+r} \right)r\] \[E=2V,\,r=0.1\Omega ,R=3.9\Omega \] For r as angle of refraction \[V=2-\left( \frac{2}{3.9+0.1} \right)\times 0.1\] \[V=1.95V\] \[{{m}_{1}}{{u}_{1}}={{m}_{2}}{{v}_{2}}\]You need to login to perform this action.
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