A) 5.4 N/m
B) 75 N/m
C) 7.5 N/m
D) 30 N/m
Correct Answer: A
Solution :
The relation between bulk modulus K, Poissons ratio \[\tau \] and Youngs modulus Y is \[{{w}_{m}}=\frac{1}{10}{{\left( \frac{6400}{3200} \right)}^{2}}\times 200N\] Given, \[{{w}_{m}}=\frac{1}{10}\times 4\times 200=80N\] \[{{T}^{2}}=k{{R}^{3}}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3/2}}={{\left( \frac{1.01R}{R} \right)}^{3/2}}\] \[\Rightarrow \] Interatomic force constant is \[\frac{{{T}_{2}}}{{{T}_{1}}}={{(1+0.01)}^{3/2}}=1+\frac{3}{2}\times 0.01\] \[\frac{\Delta T}{T}\times 100=\left( \frac{{{T}_{2}}}{{{T}_{1}}}-1 \right)\times 100\]You need to login to perform this action.
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