A) 500
B) 1000
C) 1250
D) 100
Correct Answer: C
Solution :
AC power gain \[\beta \] \[k\Omega \] \[\mu F\] where \[{{A}_{V}}\] is voltage gain and \[(h=6.6\times {{10}^{-34}}J-s1cal=4.2J)\] is AC current gain. Also, \[\overset{0}{\mathop{A}}\,\] Given, \[R=\alpha \] Hence, \[\alpha \] \[\mu k\] \[\mu k\] Now, AC power gain \[\mu k\] \[\mu k\]You need to login to perform this action.
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